optimal protocol fee
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@@ -53,7 +53,7 @@ Evaluating:
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- $h(1) = 0$
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- $h\!\left(\frac{1}{3}\right) = \frac{1}{3} \cdot \left(\frac{2}{3}\right)^2 = \frac{4}{27}$
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The maximum occurs at **$g^* = \frac{1}{3}$**, giving:
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The maximum occurs at $g^* = \frac{1}{3}$, giving:
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| Quantity | Value |
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|-----------------------|---------------------------|
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